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Friday, April 11, 2014

Logarithmic Functions by professor Atef

Logarithms are the "opposite" of exponents, just as subtraction is the opposite of addition and division is the opposite of multiplication. Logs "undo" exponentials. Technically speaking, logs are the inverses of exponentials.
In practical terms, I have found it useful to think of logs in terms of The Relationship:

On the left-hand side above is the exponential statement "y = bx". On the right-hand side above, "logb(y) = x" is the equivalent logarithmic statement, which is pronounced "log-base-b of y equals x"; The value of the subscripted "b" is "the base of the logarithm", just as b is the base in the exponential expression "bx". And, just as the base b in an exponential is always positive and not equal to 1, so also the base b for a logarithm is always positive and not equal to 1. Whatever is inside the logarithm is called the "argument" of the log. Note that the base in both the exponential equation and the log equation (above) is "b", but that the x and y switch sides when you switch between the two equations.

If you can remember this relationship (that whatever had been the argument of the log becomes the "equals" and whatever had been the "equals" becomes the exponent in the exponential, and vice versa), then you shouldn't have too much trouble with logarithms.

By the way: If you noticed that I switched the variables between the two boxes displaying "The Relationship", you've got a sharp eye. I did that on purpose, to stress that the point is not the variables themselves, but how they move.
  • Convert "63 = 216" to the equivalent logarithmic expression.
    To convert, the base (that is, the 6)remains the same, but the 3 and the 216 switch sides. This gives me:
      log6(216) = 3  
  • Convert "log4(1024) = 5" to the equivalent exponential expression.
    To convert, the base (that is, the 4) remains the same, but the 1024 and the 5 switch sides. This gives me:
      45 = 1024

3 comments:

  1. Yasmin, this actually helped me! Logs are so hard for me to understand but I really like the way you broke it down and looked at the relationship. I need to visually see something to understand it and that is exactly what you did for me. :) Good Job!!!

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  2. I've really struggled with logarithms so this was so helpful! You did a really great step by step explanation so thank you!

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  3. yasmin,

    very nice lesson and good job of using the term "relationship" as a buzz word!

    professor little

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